Chemical Engineering - Industrial Organic Chemistry

Full exam

Chimica Industriale Or ganica - Tema 17-06-19 Dati per la risoluzione dei punti 1), 2), 3) e 4) Vettori: EB, B, T ≔ a−20.5 −31.3 −24.1 ⎡ ⎢ ⎢⎣⎤ ⎥ ⎥⎦ ― ― ― J ⋅ mol K≔ b0.6 0.47 0.52 ⎡ ⎢ ⎢⎣⎤ ⎥ ⎥⎦ ― ― ― J ⋅ mol K 2 ≔ c⋅ −3.08 −3.11 2.94 ⎡ ⎢ ⎢⎣⎤ ⎥ ⎥⎦10 −4 ― ― ― J ⋅ mol K 3 ≔ d⋅ 3.52 8.52 6.12 ⎡ ⎢ ⎢⎣⎤ ⎥ ⎥⎦10 −8 ― ― ― J ⋅ mol K 4 ≔ c PL 184 172 157 ⎡⎢ ⎢⎣⎤ ⎥ ⎥⎦ ― ― ― J ⋅ mol K≔ ΔH ev 8580 7344 8025 ⎡⎢ ⎢⎣⎤ ⎥ ⎥⎦ ― ― cal mol ≔ P flash 4bar ≔ A4.40536 4.60362 4.54436 ⎡ ⎢ ⎢⎣⎤ ⎥ ⎥⎦≔ B1695.026 1701.073 1738.123 ⎡ ⎢ ⎢⎣⎤ ⎥ ⎥⎦≔ C−23.698 20.806 0.394 ⎡ ⎢ ⎢⎣⎤ ⎥ ⎥⎦≔ P rif 1bar ≔ c P((T)) + + + a⋅ bT⋅ cT2 ⋅ dT 3 ≔ Pev ((T)) ⎛ ⎜ ⎜⎝10 − A― ― ― B + ―T KC ⎞ ⎟ ⎟⎠bar ≔ T NB = − ― ― ― ― ― ⋅ BK − Alog ((1.013 )) ⋅ CK408.953 349.152 382.558 ⎡ ⎢ ⎢⎣⎤ ⎥ ⎥⎦K≔ k ((T)) ― ― ― Pev ((T)) Pflash ≔ z0.6 0.3 0.1 ⎡ ⎢ ⎢⎣⎤ ⎥ ⎥⎦≔ F100 ― ― mol hr≔ F 1 = ⋅ Fz60 30 10 ⎡⎢ ⎢⎣⎤ ⎥ ⎥⎦ ― ― mol hr 1) Teb e Tdew della miscela di alimentazione ≔ T400K ＝ ∑ = i0 2 ⋅ zik((T))i 1 ≔ T eb = find ((T)) 438.279K ≔ T400K ＝ ∑ = i0 2 ― ― zi k((T))i 1 ≔ T dew = find ((T)) 454.537K 2) Tflash e grado di vaporizzazione ≔ RL EB = ⋅ 0.95F10 57 ― ― mol hr ≔ T300K≔ α0.6 ＝ ∑ = i0 2 ― ― ― ― ― ― ⋅ zi⎛ ⎝ − k ((T))i 1⎞ ⎠ + 1⋅α ⎛ ⎝ − k ((T))i 1⎞ ⎠ 0＝⋅ ⋅ F (( − 1α )) ― ― ― ― ― ― z0 + 1⋅α ⎛ ⎝ − k ((T))0 1⎞ ⎠ RL EB ≔ T flash α ⎡ ⎢⎣⎤ ⎥⎦= find (( , Tα )) 440.164K 0.089 ⎡ ⎢⎣⎤ ⎥⎦ 3) F2 (liquido), F3 (vapore) e composizioni della fase liquida ≔ F 2 = ⋅ (( − 1α )) F91.135 ― ― mol hr≔ F 3 = − FF2 8.865 ― ― mol hr ≔ x= → ― ― ― ― ― ― ― ― ― ― ― ― ― z + 1⋅α ⎛⎝ − k ⎛⎝Tflash ⎞⎠ 1⎞⎠ 0.625 0.274 0.1 ⎡ ⎢ ⎢⎣⎤ ⎥ ⎥⎦≔ y= → ― ― ― ⋅ xk ⎛⎝Tflash ⎞⎠ 0.338 0.562 0.099 ⎡ ⎢ ⎢⎣⎤ ⎥ ⎥⎦ 4) Calore fornito nell'evaporatore normalizzato per mole di portata F2 Riferimento: liquido alla temperatura di flash ---> H2 = 0, Q = H4 ≔ T 4 650K ≔ Q ev = ⋅ F 2 ∑ = i0 2 ⋅ xi ⎛ ⎜ ⎜ ⎜ ⎜⎝+ + ⌠ ⎮⌡dTflash TNBi cPL i TΔH evi ⌠ ⎮⌡dTNBi T4 cP((T))i T⎞⎟ ⎟ ⎟ ⎟⎠ ⎛⎝ ⋅ 1.973 10 3⎞⎠W = ― ― Qev F2 ⎛⎝ ⋅ 7.795 10 4⎞⎠― ―J mol Dati per la risoluzione dei punti 5), 6) e 7) Vettori: EB, B, T, H2O, Sty, H2 ≔ a−20.5 −31.3 −24.1 32.1 71.2 27 ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢⎣⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥⎦ ― ― ― J ⋅ mol K≔ b0.6 0.47 0.52 0.002 0.05 0.009 ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢⎣⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥⎦ ― ― ― J ⋅ mol K 2 ≔ c⋅ −3.08 −3.11 2.94 0.105 6.48 −0.137 ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢⎣⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥⎦10 −4 ― ― ― J ⋅ mol K 3 ≔ P4bar ≔ d⋅ 3.52 8.52 6.12 −0.358 −69.9 76.1 ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢⎣⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥⎦10 −8 ― ― ― J ⋅ mol K 4 ≔ ΔHf ⋅ 29.8 82.9 12.4 −242 147.5 0 ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢⎣⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥⎦10 3― ―J mol≔ ν−1 0 0 0 1 1 ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢⎣⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥⎦ ≔ T rif 298K ≔ c P((T)) + + + a⋅ bT⋅ cT2 ⋅ dT 3 ≔ ratio EBtoSTEAM ―1 10 5) T7 e composizioni in uscita da R1 ≔ T 5 950K= ⋅ F 2 x0 57 ― ― mol hr ≔ F 5 = ― ― ― ― ― ⋅ F2 x0 ratio EBtoSTEAM 570 ― ― mol hr= ⋅ F 2 x1 25.016 ― ― mol hr = ⋅ F 2 x2 9.119 ― ― mol hr ≔ F 6 57 25.016 9.119 570 0 0 ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢⎣⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥⎦ ― ― mol hr ≔ H 5 = ⋅ F 63 ⎛ ⎜ ⎜ ⎜⎝+ ΔH f3 ⌠ ⎮⌡d298K T 5 cP((T))3 T⎞⎟ ⎟ ⎟⎠⋅ −3.453 10 4W ≔ H 6((T)) ∑ = i0 5 ⋅ F6i ⎛ ⎜ ⎜ ⎜⎝+ ΔH fi ⌠ ⎮⌡d298K T cP((T))i T⎞⎟ ⎟ ⎟⎠ ≔ H 4 = ∑ = i0 2 ⋅ ⋅ F 2 xi ⎛ ⎜ ⎜ ⎜⎝+ ΔH fi ⌠ ⎮⌡d298K T 4 cP((T))i T⎞⎟ ⎟ ⎟⎠ ⎛⎝ ⋅ 2.752 10 3⎞⎠W ≔ T800K ＝ + H 5 H4 H6((T)) ≔ T6 = find ((T)) 793.985K≔ H 6 = H 6⎛⎝T6⎞⎠ ⋅ −3.178 10 4W ≔ F out ((λ)) + F6 ⋅ νλ≔ y ((λ)) ― ― ― ― Fout ((λ)) ∑F out ((λ)) ≔ a ((λ)) ⋅ ― ―P P rif y((λ)) ≔ ΔG R((T)) ⎛ ⎜⎝− 127619.9 ⋅134.02 ―T K⎞ ⎟⎠― ―J mol ≔ H out (( , λT )) ∑ = i0 5 ⋅ F out ((λ))i ⎛ ⎜ ⎜ ⎜⎝+ ΔH fi ⌠ ⎮⌡d298K T cP((T))i T⎞⎟ ⎟ ⎟⎠≔ K eq((T)) exp⎛ ⎜⎝― ― ― ― −ΔG R((T)) ⋅ RT⎞ ⎟⎠ ≔ T600K≔ λ30 ― ― mol hr ＝ K eq((T)) ∏ = i0 5 a((λ))iν i ＝ H6 Hout (( , λT )) ≔ T 7 λ1 ⎡ ⎢⎣⎤ ⎥⎦= find (( , Tλ )) 755.262K 0.003 ― ― mol s ⎡ ⎢ ⎢⎣⎤ ⎥ ⎥⎦= λ 1 10.769 ― ― mol hr = y ⎛⎝λ1⎞⎠ 0.069 0.037 0.014 0.848 0.016 0.016 ⎡⎢ ⎢ ⎢ ⎢ ⎢ ⎢⎣⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥⎦= F out ⎛⎝λ1⎞⎠ 46.231 25.016 9.119 570 10.769 10.769 ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢⎣⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥⎦ ― ― mol hr≔ χ overall 0.4 6) Grado di avanzamento della reazione in R2 normalizzato rispetto alle moli di F2 ≔ F outEB = ⋅ F 60 ⎛⎝ − 1χ overall ⎞⎠ 34.2 ― ― mol hr≔ λ 2 = − F out ⎛⎝λ1⎞⎠0 FoutEB 12.031 ― ― mol hr = ―λ2 F2 0.132 ≔F 7 Fout ⎛⎝λ1⎞⎠ ≔ F8 F7 ≔ F9 = + F 8 ⋅ νλ 2 34.2 25.016 9.119 570 22.8 22.8 ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢⎣⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥⎦ ― ― mol hr 7) T9 e calore scambiato nello scambiatore (normalizzato su F2) ≔ y 9 = ― ―F9 ∑F 9 0.05 0.037 0.013 0.833 0.033 0.033 ⎡⎢ ⎢ ⎢ ⎢ ⎢ ⎢⎣⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥⎦≔ a 9 = ⋅ ― ―P P rif y9 0.2 0.146 0.053 3.334 0.133 0.133 ⎡⎢ ⎢ ⎢ ⎢ ⎢ ⎢⎣⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥⎦ ≔ T800K ＝ K eq((T)) ∏ = i0 5 a9iν i ≔ T9 = find ((T)) 827.93K ≔ H 9 = ∑ = i0 5 ⋅ F9i ⎛ ⎜ ⎜ ⎜⎝+ ΔH fi ⌠ ⎮⌡d298K T 9 cP((T))i T⎞⎟ ⎟ ⎟⎠⋅ −3.01 10 4W ≔ H 8((T)) ∑ = i0 5 ⋅ F8i ⎛ ⎜ ⎜ ⎜⎝+ ΔH fi ⌠ ⎮⌡d298K T cP((T))i T⎞⎟ ⎟ ⎟⎠ ≔ T800K ＝ H 9 H8((T)) ≔ T8 = find ((T)) 871.087K ≔ H 7 = ∑ = i0 5 ⋅ F8i ⎛ ⎜ ⎜ ⎜⎝+ ΔH fi ⌠ ⎮⌡d298K T 7 cP((T))i T⎞⎟ ⎟ ⎟⎠⋅ −3.178 10 4W ≔ Q ex = − H 8⎛⎝T8⎞⎠ H7 ⎛⎝ ⋅ 1.676 10 3⎞⎠W= ― ― Qex F2 ⎛⎝ ⋅ 6.62 10 4⎞⎠― ―J mol