Informazioni sul documento
- Università
- Politecnico di Milano
- Corso di laurea
- Management Engineering
- Materia
- GAME THEORY
- Classificazione
- Esame · Esame completo
- Contenuto
- Testo d’esame
- Formato originale
- Testo
- Testo ricercabile
Esame completo di GAME THEORY per il corso di Management Engineering presso Politecnico di Milano. Materiale proveniente dall’archivio storico Studwiz e classificato per la consultazione online.
Esame completo di GAME THEORY per il corso di Management Engineering presso Politecnico di Milano. Materiale proveniente dall’archivio storico Studwiz e classificato per la consultazione online.
Qualità dell’importazione: il testo è stato estratto direttamente dal documento originale.
Passaggi rappresentativi riconosciuti nelle diverse parti del materiale. Il testo completo resta presente nella pagina per la ricerca, mentre l’anteprima compatta rende più semplice la lettura.
GAME THEORY 5 cfu February 3 2020 Surname: Name: Matricola: Exercise 1 Given the following bimatrix game, where a, b are real parameters (3, 2) (4 , 6) (4 , 4) (a, 3) (3 , 0) (10 , 0) (20, 0) (0 , 0) (4 , b) 1. find the Nash equilibria in pure strategies for different values of a, b∈ R; 2. find the best reaction of the first player to the strategy ( 1 3 , 1 3 , 1 3 ) of the second player; 3. for a = 25 say if there is a NE profile such that the first player plays the third row with positive probability; 4. find for which values of a and b there is a Nash equilibrium such that the first player plays only the third row. Answer of exercise 1 1. NE outcomes: (4, 6) for all a, b, (20, 0) if b≤ 0, a≤ 20, (a, 3) if a≥ 20 and all b; 2. Evaluating the utilities form the three rows we get (0, 0, 1), if a < 11 (0, 1, 0), if a > 11 (0, p, 1− p) otherwise 3. Such a NE profile cannot exist since the last row is strictly dominated by the second one; 4. It must be b≤ 0; suppose player two plays (q, 1− q, 0). Then it must be 3q + 4− 4q≤ 20q, aq + 3− 3q≤ 20q. this implies a≤ 20, q ≥ max{ 4 21 , 3 23− a}. 1 Exercise 2 Let (N, v) be the following TU game: N ={1, . . . , n}, v(S) = ( s + 1)! (where S is a nonempty coalition and s =|S|). 1. Find the Shapley value for every n; 2. Find the core when n = 3. Answer of exercise 2 1. All players are symmetric thus the Shapley value is the vector ( (n+1)! n , . . . , (n+1)! n ); 2. The core of the game is co {(2, 4, 18), (4, 2, 18), (18, 2, 4), (18, 4, 2), (2, 18, 4), (4, 18, 2)}. Exercise 3 From a pile of cards the two players can take either 3 or 4 cards. The player that cannot move looses. 1. Tell who is the winner if there are 10 cards and how she wins; 2. Find all P and N positions. Answer of exercise 3 1. the first player, she takes 3…
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