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Chapter 06 Exercises collection

Divisi per argomento di RELIABILITY, SAFETY AND RISK ANALYSIS C per il corso di Energy Engineering presso Politecnico di Milano. Materiale proveniente dall’archivio storico Studwiz e classificato per la consultazione online.

RELIABILITY, SAFETY AND RISK ANALYSIS CDivisi per argomento

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Divisi per argomento di RELIABILITY, SAFETY AND RISK ANALYSIS C per il corso di Energy Engineering presso Politecnico di Milano. Materiale proveniente dall’archivio storico Studwiz e classificato per la consultazione online.

Qualità dell’importazione: il testo è stato estratto direttamente dal documento originale.

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Passaggi rappresentativi riconosciuti nelle diverse parti del materiale. Il testo completo resta presente nella pagina per la ricerca, mentre l’anteprima compatta rende più semplice la lettura.

Pagina 1

Chapter 6 Availability and maintainability 6.1 Compressor A compressor is designed for Td = 5 years of operation. There are two significant contributions to the failure. The first is due to wear (W) of the thrust bearing and is described by a Weibull distribution 𝑓(𝑡) = 𝑚 𝜃 (𝑡 𝜃) 𝑚−1 𝑒 [−(𝑡 𝜃) 𝑚 ] with θ= 7.5 year and m = 2.5 . The second, which includes ali other causes (O) is described by a constant failure rate of λO = 0.013 year-1. l. What is the reliability if no preventive maintenance is performed over the 5-year design life? 2.If the reliability of the 5-year design life is to be increased to at least 0.9 by periodically replacing the thrust bearing, how frequently must it be replaced? 3. Suppose that the probability of fault bearing replacement causing failure of the compressor is p = 0.02. What will the design-life reliability be with the replacement program decided in 2)? 6.2 Sequential and staggered maintenance scheme of a one-out-of-two system Consider a one-out-of two system of identical components with constant failure rate λ. The testing and repair of each component last for τr hours. l. In the sequential maintenance scheme, the two components are tested one after the other, τ being the time between the end of the previous maintenance of the second component and the beginning of the next maintenance of the first one (in other words, every τ hours we test both components in sequence). Find the average unavailability of the system. 2. In the staggered maintenance scheme, the first component maintenance starts at kτ, k < l , where τ is the time interval between the end of the previous maintenance of the second component and the beginning of the next maintenance of the same second component. Find the average unavailability of the system.

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Prima pagina: Chapter 06 Exercises collection