Informazioni sul documento
- Università
- Politecnico di Milano
- Corso di laurea
- Chemical Engineering
- Materia
- Apllied Mechanics
- Classificazione
- Appunti · Divisi per argomento
- Formato originale
- Testo
- Testo ricercabile
Divisi per argomento di Apllied Mechanics per il corso di Chemical Engineering presso Politecnico di Milano. Materiale proveniente dall’archivio storico Studwiz e classificato per la consultazione online.
Divisi per argomento di Apllied Mechanics per il corso di Chemical Engineering presso Politecnico di Milano. Materiale proveniente dall’archivio storico Studwiz e classificato per la consultazione online.
Qualità dell’importazione: il testo è stato estratto direttamente dal documento originale.
Passaggi rappresentativi riconosciuti nelle diverse parti del materiale. Il testo completo resta presente nella pagina per la ricerca, mentre l’anteprima compatta rende più semplice la lettura.
2. Forced motion of Single Degree Of Freedom Systems (SDOF) Let us consider the SDOF system illustrated in Figure 2.1. The mass m is subjected to a harmonic force of frequency 2f π= Ω . The maximum amplitude of the force is F o while β is the phase with respect to initial time. Therefore, the force can be expressed as: oF( ) F cos ( )tt β= Ω+ (2.1) Figure 2.1 Forced SDOF system Let us denote as x the absolute displacement of the mass with respect to the s tatic equilibrium posi tion. The equation of motion is given by: ooF cos ( ) F cos ( )mx cx kx t βϑ+ + = Ω+ = (2.2) The phase β indicates that the external force may not reach its maximum level at time t = 0. In accordance with Euler’s notation it is possible to write: [ ] () ooF F c o s () s i n ()ite t itβ ββΩ+ = Ω+ + Ω+ (2.3) Therefore, eq.(2.3) can be rewritten as: () oRe F itmx cx kx e βΩ+++ = (2.4) In case of a sinusoidal excitation the motion equation is: ooF sin ( ) F sin ( )mx cx kx t βθ+ + = Ω+ = (2.5) Eq.(2.5) can be rewritten as: () oIm F itmx cx kx e βΩ+++ = (2.6) In a more general case we can write: ( ) () ooFF it imx cx kx e e βϑΩ+++ = = (2.7) where we implicitly assume to consider the real or the imaginary part of the complex term at the right side of eq.(2.7) depending on the type of the harmonic excitation ( )F t (cosine or sine function). The solution of this differential equation is: () () () gsxt x t x t= + (2.8) The term ()gxt is the general solution. It coincides with the solution of eq.(2.7), that is the system response of the free motion. The second tem, ()sxt , is the steady state solution. It only depends on the system excitation. In case of an underdamped system the contribution of the term ()gxt nullifies after a suitably long time interval. For linear systems…
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