xx 05 20 simulation sol

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01. Exam simulation 07.05.2020 1 EXERCISE 1 PART 1 We have to design the bay. The dimensions after the computations will be: - 𝐿 = 0,1 ∗ 4 + 0,8 ∗ 2 = 2 𝑚 - 𝐻 = 0,1 + 0,15 + 1,5 = 1,75 𝑚 - 𝐷 = 1,2 + 0,2 2 = 1,3 𝑚 The next step is to determine the number of the levels 𝑁𝐿 = 𝑚𝑖𝑛{⌊ 8,5 1,75⌋ ; ⌊ 7,5 1,75⌋} = 𝑚𝑖𝑛{4; 5} = 4 𝑙𝑒𝑣𝑒𝑙𝑠 We know from the text that the length of the aisle is fixed. So, I do not have to determine the optimal shape because I have these constraints. Since the lengths of aisle is fixed (50m), the number of columns is fixed. So, the number of aisles is just a consequence: - 𝑁𝐶 = 50 2 = 25 𝑐𝑜𝑙𝑢𝑚𝑛𝑠 [𝑜𝑡ℎ𝑒𝑟𝑤𝑖𝑠𝑒, 𝑁𝐶 = ⌈ 𝑆𝐶 2∗𝑁𝐴∗𝑁𝑃𝐵∗𝑁𝐿⌉ ] - 𝑁𝐴 = ⌊ 𝑆𝐶 2∗𝑁𝐶∗𝑁𝑃𝐵∗𝑁𝐿⌋ = ⌊ 4.000 2∗4∗2∗25⌋ = 10 𝑎𝑖𝑠𝑙𝑒𝑠 The problem is easier than the traditional one solved in class: we do not have to find the optimal shape. Now we have to find U: - 𝐿𝑚𝑜𝑑𝑢𝑙𝑒 = 2 ∗ 𝐷 + 𝐴𝑊 = 2 ∗ 1,3 + 2,8 = 5,4 𝑚 - 𝑈 = 𝑁𝐴 ∗ 𝐿𝑚𝑜𝑑𝑢𝑙𝑒 = 10 ∗ 5,4 = 54 𝑚 Now we go through the computation of the cycle time: 𝑇𝑆𝐶 = 𝐹𝑇 + 𝑉𝑇 = 𝐹𝑇 + [ 𝑃 𝑆𝐻 + 𝑆 𝑆𝑉 ] = = 𝐹𝑇 + 2 ∗ ( 𝑈 2 + 𝑉 2 + 𝑊𝑎𝑐𝑐𝑒𝑠𝑠 𝑎𝑖𝑠𝑙𝑒) ∗ 1 𝑆𝐻 + 2 ∗ 𝐻 ∗ ( 𝑁𝐿−1 2 ) ∗ 1 𝑆𝑉 = = 50 + 2 ∗ ( 54+50 2 + 3) ∗ 1 2 + 1,75 ∗ 4−1 0,4 = 50 + 55 + 13,125 = 118,125𝑠𝑒𝑐 𝑇𝐶𝑡𝑟𝑢𝑐𝑘 = UF ∗ 3600 TSC = 1 ∗ 3600 118,125 = 30,48 𝑠𝑒𝑐/ℎ # 𝑡𝑟𝑢𝑐𝑘 = ⌈ 𝑡ℎ𝑟𝑜𝑢𝑔ℎ𝑝𝑢𝑡 𝑐𝑎𝑝𝑎𝑐𝑖𝑡𝑦 𝑟𝑒𝑞𝑢𝑖𝑟𝑒𝑑 𝑇𝐶𝑡𝑟𝑢𝑐𝑘 ⌉ = ⌈ 160 30,48⌉ = ⌈5,25⌉ = 6 𝑡𝑟𝑢𝑐𝑘𝑠 // this was the first part; it is worth 24 points out of 30. If the mistake in the formula is -2 or -3 points, for a computation error is -1, for worst error of concepts more points will be removed (like if we would have used the AUR here -10 points would have been removed). PART 2 Since the I/O point is in the corner, the iso-time curve will be something like the one in the drawing on the right. If the I/O point would have been in the middle, in this case we would have done…