Document information
- University
- Politecnico di Milano
- Degree programme
- Mechanical Engineering
- Subject
- Sistemi Energetici L
- Academic year
- 2012-2013
- Classification
- Exam · Full exam
- Content
- Exam paper only
- Original format
- Text
- Searchable text
Study material for Sistemi Energetici L, shared by the Studwiz community and reviewed by moderators.
Study material for Sistemi Energetici L, shared by the Studwiz community and reviewed by moderators.
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Esercizio 1: Degasatore preriscaldatore 5 Vapore da turbina: p, bar 7 39.8 T saturazione, °C 165 250 Dhcond, kJ/kg 2066 1715 cp medio cond, kJ/kg-K 4.76 Acqua da preriscaldare G in, kg/s 150 Tin, °C 130 210 cp medio, kJ/kg-K 4.27 4.47 DT minimo vapore-acqua riscaldata = 3 °C DT minimo condensato-acqua in ingresso = 5 °C c) Degasatore: T acqua in uscita 165 °C DT acqua 35 °C Dh acqua 149.5 kJ/kg Q acqua 22418 kW G vapore 10.85 kg/s G acqua out 160.85 kg/s Preriscaldatore n°5: G acqua in 160.85 kg/s T acqua in uscita 247 °C DT acqua 37 °C Dh acqua 165.39 kJ/kg-K Q acqua 26603 kW T out condensato 215 °C DT condensato 35 °C Dh sottoraffr. condensa 166.6 kJ/kg Dh cond + sottoraffredd. 1881.6 kJ/kg G vapore 14.14 kg/s Esercizio 2: LHV CH4 802 MJ/kmole eccesso aria = 10 % xO2 aria = 0.21 xN2 aria = 0.79 MMCH4, kg/kmole 16 MMO2, kg/kmole 32 MMN2, kg/kmole 28 MMCO2, kg/kmole 44 MMH2O, kg/kmole 18 a) CH4 + 2O2 -> CO2 + 2H2O λstech = 2 moliO2/moleCH4 N2/O2 aria = 3.76 moliN2/moliO2 λstech = 9.52 moli aria/moleCH4 λ = 10.48 moli aria/moleCH4 MMaria = 28.84 kg/kmole α = 18.88 kgaria/kgCH4 Gfumi = 19.88 kgfumi/kgCH4 zCO2 = 1 kmoliCO2/kmoleCH4 165°C 130°C T Q 130°C T Q 250°C zH2O = 2 kmoliH2O/kmoleCH5 zO2 = 0.20 kmoliO2/kmoleCH4 zN2 = 8.28 kmoliN2/kmoleCH4 ztot = 11.48 kmoli_fumi/kmoleCH4 xCO2 = 0.087 kmoliCO2/kmolefumi xH2O = 0.174 kmoliH2O/kmolefumi xO2 = 0.017 kmoliO2/kmolefumi xN2 = 0.721 kmoliN2/kmolefumi MMfumi = 27.7 kg/kmole yCO2 = 0.138 kgCO2/kgfumi yH2O = 0.113 kgH2O/kgfumi yO2 = 0.020 kgO2/kgfumi yN2 = 0.728 kgN2/kgfumi b) cpCO2 = 39.2 kJ/kmole-K cpH2O = 34.3 kJ/kmole-K cpO2 = 30 kJ/kmole-K cpN2 = 29.5 kJ/kmole-K cp, fumi = 31.19 kJ/kmole-K cp, fumi = 1.13 kJ/kg-K Qloss, irr = 1 % Tcamino = 90 °C Tambiente = 25 °C Qcamino = 73 kJ/kgfumi Qcamino = 1454 kJ/kgCH4 LHV CH4 =…
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