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- University
- Politecnico di Milano
- Degree programme
- Mechanical Engineering
- Subject
- Energy Systems LM
- Academic year
- 2025-2026
- Classification
- Exam · Full exam
- Content
- Solution only
- Original format
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Study material for Energy Systems LM, shared by the Studwiz community and reviewed by moderators.
Energy Systems LMFull exam
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PROBLEM 2: Data GT power, MWe 50 Net electric efficiency, % 36% Air temperature, °C 15 GT heat loss, %LHV 0,50% Mechanical-electric efficiency, % 98% Air/fuel ratio, kga/kgf 55 Specific heat capacity cp of air, kJ/(kg K) 1,02 Specific heat capacity cp of flue gas, kJ/(kg K) 1,05 PV plant capacity, MWe 15 Number of equivalent hours of PV plant, heq/year 1800 GT operating hours, h/year 8760 Solution 1) Qfuel = Pe / eta,e = 138,89 MWLHV Fuel flow rate: mf = Qfuel / LHV = 2,772 kg/s Air flow rate: ma = 152,47 kg/s ma*cp,a*(Ta-25) + Qfuel = Pe / eta,me + Qloss + (mf+ma)*cp,g*(TOT-25) --> TOT = 550,2 °C 2) Methane emission factor: ECO2,gn = 1 kmoleCO2/kmoleCH4 2,75 kgCO2/kgCH4 0,055 kgCO2/MJLHV GT specific emission: ECO2,gt = ECO2,gn / eta,e * 3600 = 548,90 kgCO2/MWh 3) Electricity from PV: EEpv = Ppv * h_eq = 27.000 MWh/y Saved CO2 = EEpv * ECO2,gt = 14.820 t/y
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