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- Politecnico di Milano
- Degree programme
- Biomedical Engineering
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- Mathematical and Numerical Methods in Engineering
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- Notes Β· Complete set
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Complete course materials for Mathematical and Numerical Methods in Engineering in the Biomedical Engineering degree programme at Politecnico di Milano. The document covers: 1 NOTES OF MATHEMATICAL METHODS Prof. F. Gazzola β A.A. 2020/21 REVIEW OF ODEs ODEs ODEs are Ordinary Differential Equations in the form: π¦!=π(π¦) ,π:πΌββββ Linear first order ODEs The linear first order ODEs are differential equation can be solved in different ways depending
Complete course materials for Mathematical and Numerical Methods in Engineering in the Biomedical Engineering degree programme at Politecnico di Milano. The document covers: 1 NOTES OF MATHEMATICAL METHODS Prof. F. Gazzola β A.A. 2020/21 REVIEW OF ODEs ODEs ODEs are Ordinary Differential Equations in the form: π¦!=π(π¦) ,π:πΌββββ Linear first order ODEs The linear first order ODEs are differential equation can be solved in different ways depending
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1 NOTES OF MATHEMATICAL METHODS Prof. F. Gazzola β A.A. 2020/21 REVIEW OF ODEs ODEs ODEs are Ordinary Differential Equations in the form: π¦!=π(π¦) ,π:πΌββββ Linear first order ODEs The linear first order ODEs are differential equation can be solved in different ways depending on their particular form, but in general they have the following form: π¦!=πΌπ¦+π½ Malthus equation The Malthus equation is the simplest linear first order ODE and its solution is often used during the resolution of more complicated ODEs: πΆππ’πβπ¦ πππππππ: <π¦!=ππ¦π¦(0)=π¦" β ππππ’π‘πππ: π¦(π‘)=π¦"π#$ Β΄ Since πΉ(π¦)=ππ¦βπΆ%(πΌ) the solution of the Cauchy problem exists and is unique Β΄ In the classical Malthus equation π is a constant, but we can generalize the solution for π(π‘) with the generalized Malthus equation, which can be solved with separation of variables Separable variables When there are variables which can be separated, such as time and space variable, we can apply the separation of variables method: π¦!=πΉ(π‘)βπΊ(π¦) Steps of resolution: i. Multiply both sides for dt: π¦!ππ‘=πΉ(π‘)βπΊ(π¦)ππ‘ ii. Separate the variables under the condition πΊ(π¦)β 0: π¦!ππ‘πΊ(π¦)=πΉ(π‘)ππ‘ iii. Integrate and then apply the initial condition in order to find the value of the constant of integration: β«π¦!ππ‘πΊ(π¦)=β«πΉ(π‘)ππ‘ Generalized Malthus equation The generalized Malthus equation is characterized by a function π(π‘) which multiply π¦ and depends on the variable π‘: π¦!π¦=π(π‘) This equation can be solved with separation of variables Steps of resolution: i. Multiply both sides for dt: π¦!π¦ππ‘=π(π‘)ππ‘ 2 ii. Assume π¦!ππ‘=ππ¦ and integrate: β«ππ¦π¦=β«π(π‘)ππ‘ iii. Assume πΈ!(π‘)=π(π‘) to be the primitive of π(π‘), so finally we obtain the solution: ln(π¦)=πΈ(π‘)+π β π¦=π&($))* =πΆπ&($) Non-separable variables There are also ODE in which the variables cannot be separated intoβ¦
First page of the document.