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- Politecnico di Milano
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- Chemical Engineering
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- Chimica Industriale
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- Exercises · By topic
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ExercisesBy topic
Esercitazione 9 Soluzione
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Chimica IndustrialeBy topic
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Risoluzione Derivazione della cinetica Stima dei parametri k0 riduzione 1.83E+09 mol/h/gcat/atm EA riduzione 1.01E+05 J/mol Stima del coefficiente alfa 0.125 Calcolo delle energie di attivazione apparente in regime chimico e per un pellet di 2 mm EA chimica 87504.85 j/mol EA pellet 2 mm 48287.71 j/mol Portata che garantisce massima produttività e conversione > 95% Fin 185 mol/h y = -10525x + 14.116 y = -5808.5x + 5.9133 -2.5 -2 -1.5 -1 -0.5 0 0.5 1 1.5 0.00124 0.00126 0.00128 0.0013 0.00132 0.00134 0.00136 0.00138 0.0014 ln (k) [mol/h/gcat/atm ] 1/T [1/K] Regime chimico Pellet 2mm Lineare (Regime chimico) Lineare (Pellet 2mm)
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