Line balancing Suppl

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1 ANOTHER CASE Operation Work content [minutes] Direct Follower 1 0.2 2 2 0.4 2 3 0.7 3 4 0.1 1 5 0.3 1 6 0.11 1 7 0.32 1 8 0.6 2 9 0.27 1 10 0.38 1 11 0.5 1 12 0.12 0 Cicle Time (CT)= 1 minute Total Work content = 4 minutes In this case we have another link, between operations 8 and 10 Operation Work content minutes 3 0.7 8 0.6 11 0.5 2 0.4 10 0.38 7 0.32 5 0.3 9 0.27 1 0.2 12 0.12 6 0.11 4 0.1 MAXDUR - TASK ORIENTED PROCEDURE (TOP) 1 2 3 4 5 Available 1;2 1;5 1 3,4 3,4 4,6,7 4,6,7 4,6 4 8 8 9,10 9 9 11 12 Allocated 2 5 1 3 3 7 7 6 4 8 8 10 9 9 11 12 Allocated Time 0.4 0.3 0.2 0.7 0.7 0.32 0.32 0.11 0.1 0.6 0.6 0.38 0.27 0.27 0.5 0.12 Cumulative Allocated Time 0.4 0.7 0.9 1.6 0.7 1.02 0.32 0.43 0.53 1.13 0.6 0.98 1.25 0.27 0.77 0.89 𝐸𝑏 = 4 5 ∗ 𝑚𝑎𝑥(0.9; 0.7; 0.53; 0.98; 0.89) = 4 5 ∗ 0.98 = 81.63% MAXDUR – STATION ORIENTED PROCEDURE (SOP) 1 2 3 Available 1;2 1;5 1 3,4 4 3 6,7,8 6,7 6 7,8 7,10 7 Allocated 2 5 1 3 4 3 8 7 6 8 10 7 Allocated Time 0.4 0.3 0.2 0.7 0.1 0.7 0.6 0.32 0.11 0.6 0.38 0.32 Cumulative Allocated Time 0.4 0.7 0.9 1.6 1 0.7 1.3 1.02 0.81 0.6 0.98 1.3 4 5 Available 7 9 11 11 12 Allocated 7 9 11 11 12 Allocated Time 0.32 0.27 0.5 0.5 0.12 Cumulative Allocated Time 0.32 0.59 1.09 0.5 0.62 𝐸𝑏 = 4 5 ∗ 𝑚𝑎𝑥(1; 0.81; 0.98; 0.59; 0.62) = 4 5 ∗ 1 = 80% MAXNFOL – TOP 1 2 3 Available 1;2 1;5 3;4;5 3;4;5 4;5;6;7 4;5;6;7 4;5;6 4;6 4 8 Allocated 2 1 3 3 7 7 5 6 4 8 Allocated Time 0.40 0.20 0.70 0.70 0.32 0.32 0.30 0.11 0.10 0.60 Cumulative Allocated Time 0.40 0.60 1.30 0.70 1.02 0.32 0.62 0.73 0.83 1.43 4 5 Available 8 9;10 9 9 11 12 Allocated 8 10 9 9 11 12 Allocated Time 0.60 0.38 0.27 0.27 0.50 0.12 Cumulative Allocated Time 0.60 0.98 1.25 0.27 0.77 0.89 𝐸𝑏 = 4 5 ∗ 𝑚𝑎𝑥(0.60; 0.70; 0.83; 0.98; 0.89) = 4 5 ∗ 0.89 = 81.63% MAXNFOL – SOP 1 2 Available 1;2 1;5 3;4;5…