Document information
- University
- Politecnico di Milano
- Degree programme
- Aerospace Engineering
- Subject
- Telecommunication Systems
- Classification
- Notes · Complete set
- Original format
- Text
- Searchable text
Complete course materials for Telecommunication Systems in the Aerospace Engineering degree programme at Politecnico di Milano. The document covers: dB/dBW/dBm cheat sheet • dB is a logarithmic ratio of powers . So saying P1 = 2 · P2 is equivalent to saying P1/P2 ≜ 3 dB, because 10 · log10 ( P1 P2 ) dB = 10 · log10(2) dB = 3 dB. The unit dBi can be treated just like dB, because it measures the gain of an antenna relative to
Complete course materials for Telecommunication Systems in the Aerospace Engineering degree programme at Politecnico di Milano. The document covers: dB/dBW/dBm cheat sheet • dB is a logarithmic ratio of powers . So saying P1 = 2 · P2 is equivalent to saying P1/P2 ≜ 3 dB, because 10 · log10 ( P1 P2 ) dB = 10 · log10(2) dB = 3 dB. The unit dBi can be treated just like dB, because it measures the gain of an antenna relative to
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dB/dBW/dBm cheat sheet • dB is a logarithmic ratio of powers . So saying P1 = 2 · P2 is equivalent to saying P1/P2 ≜ 3 dB, because 10 · log10 ( P1 P2 ) dB = 10 · log10(2) dB = 3 dB. The unit dBi can be treated just like dB, because it measures the gain of an antenna relative to an isotropic antenna which has the gain of 1 (0 dB). • dBm and dBW is a (logarithmic) unit to measure powers. Since dB is a ratio of powers, dBm and dBW are defined by forming the ratio of the power you want to express relative to a reference power, which is 1 W for dBW and 1 mW for dBm. Formally speaking, PT|dBm = 10 · log10 ( PT 1 mW ) PT|dBW = 10 · log10 ( PT 1 W ) = PT|dBm − 30 dB Consequently, two things are okay : • Starting with a power (dBW or dBm) you can add and subtract ratios (dB or dBi) as often as you like and you still have a power (dBW or dBm): P1 · G1/L1 = P2 ⇔ 10 · log10 ( P1 · G1/L1 1 W ) = 10 · log10 P2 1 W ⇔ P1|dBW + G1|dB − L1|dB = P2|dBW • Subtracting two powers (dBW or dBm) which is equivalent to computing their ratio (dB): P1 P2 ≜ 10 · log10 ( P1 P2 ) dB = 10 · log10 ( P1 1 W ) − 10 · log10 ( P2 1 W ) = P1|dBW − P2|dBW = 10 · log10 ( P1 1 mW ) − 10 · log10 ( P2 1 mW ) = P1|dBm − P2|dBm Both powers must have the same unit, do not mix dBW and dBm. Short hand notation for things that are okay : dBW ± dB = dBW dBm ± dB = dBm dBW − dBW = dB dBm − dBm = dB 1 On the other hand, the following things are not okay: • Never ever multiply dBW with dB! I have seen students claiming that a power of PT =10 W with an antenna gain of GT =10 gives an effective radiated power of 100 dBW. No! 100 dBW is 10 Gigawatts! Multiply in linear scale, that becomes addition in logarithmic scale: PT · GT = 10 W · 10 = 100 W ≜ 20 dBW ⇔ PT|dBW + GT|dBi = 10 dBW + 10 dBi = 20 dBW • Never add a bunch of…
First page of the document.