← Back
ExamFull examSolution only

Soluz040714

Study material for Sistemi Energetici L, shared by the Studwiz community and reviewed by moderators.

Sistemi Energetici LFull exam

Document information

What's included in this study material

Study material for Sistemi Energetici L, shared by the Studwiz community and reviewed by moderators.

Import quality: text was extracted directly from the original document.

Extracted content from the document

Representative passages recognised in different parts of the material. The full extracted text remains available to search, while this compact preview makes the page easier to read.

Page 1

Esercizio 1: Dati: Gacqua = 20 kg/s Tacqua in = 40 °C Tacqua out = 97 °C Tsat vap = 100 °C h liq sat = 419 kJ/kg h vap sat = 2676 kJ/kg xv = 95 % cp acqua = 4.2 kJ/kg/K U = 800 W/m2-K Gacqua' = 10 kg/s Tsat vap' = 86 °C h liq sat' = 360 kJ/kg h vap sat' = 2653 kJ/kg xv' = 93 % Assunzioni: DTce = 5 °C Tcond out = 45 °C Q Thot Tcold Dh cond = 2144 kJ/kg 0 100 97 Dh sc = 231 kJ/kg 4322 100 45.5 Dh hot side = 2375 kJ/kg 4788 45 40 Q rig = 4788 kW Gvap = 2.016 kg/s Qcond = 4322 kW Qsc = 466 kW Tacqua @ Qsc = 45.5 °C DT1 sc = 5 °C DT2 sc = 54.5 °C DTml sc = 20.71 °C UA sc = 22484 W/K DT1 cond = 54.5 °C DT2 cond = 3 °C DTml cond = 17.75 °C UA cond = 243498 W/K UA tot = 265982 W/K A tot = 332 m2 DT he' = 1.0 °C <- valore di primo tentativo, verosimilmente inferiore ai 3°C del caso on design Tacqua out' = 85.0 Qrig' = 1890 kW Dh cond' = 2132 kJ/kg Tcond out' = 45 °C Dh sc' = 172 kJ/kg Dhtot' = 2305 kJ/kg Gvap' = 0.820 kg/s Qcond' = 1749 kW Qsc' = 141 kW Tacqua @ Qsc' = 43.4 °C DT1 sc' = 5 °C DT2 sc' = 41.6 °C DTml sc' = 17.29 °C UA sc' = 8170 W/K DT1 cond' = 41.6 °C DT2 cond' = 1.0 °C DTml cond' = 10.90 °C UA cond' = 160472 W/K UA tot' = 168642 W/K A tot' = 211 m2 <- valore minore della superficie effettiva => iterazione successiva con DThe inferiore 0 20 40 60 80 100 120 0 1000 2000 3000 4000 5000 6000 T, °C Q, kW Esercizio 2: eccesso aria = 10 % xO2 ox = 0.6 xN2 ox = 0.4 MMO2 32 kg/kmole MMN2 28 kg/kmole MMCH4 16 kg/kmole LHVCH4 = 50 MJ/kg Tfumi camino 110 °C = 383.15 K Tamb = 25 °C = 298.15 K ENOx = 10 mg/MJLHV MMNOx = 46 kg/kmole Assunzione: Altre perdite di combu 1% a) CH4 + 2O2 -> CO2 + 2H2O λstechCH4 = 2 moliO2/moleCH4 N2/O2 ox = 0.67 moliN2/moliO2 λstech = 3.33 moli ox/moleCH4 λ = 3.67 moli ox/moleCH4 MMox = 30.4 kg/kmole α = 6.97 kgox/kgCH4 Gfumi = 7.97 kgfumi/kgCH4…

Preview

First page of the document.

First page: Soluz040714