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Spettri

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Misure e Strumentazione IndustrialeBy topic

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ES 1 Rappresentare lo spettro dei seguenti segnali     8142sin3102cos2 )9 23142cos652cos3 )8 5362cos5 )7 5362cos5 )6 5362cos5 )5 392sin )4 3 756.12cos )3 356.12cos )2 102cos3 )1                                                       tty tty ty ty ty ty ty ty ty          SOLUZIONI ES 1 1) 0 2 4 6 8 10 12 14 16 18 20 0 0.5 1 1.5 2 2.5 3 modulo [eu] 0 2 4 6 8 10 12 14 16 18 20 -150 -100 -50 0 50 100 150 freq [Hz] fase [deg] 2) Hzf f srad 22 2 /56.12        0 2 4 6 8 10 12 14 16 18 20 0 0.2 0.4 0.6 0.8 1 modulo [eu] 0 2 4 6 8 10 12 14 16 18 20 -150 -100 -50 0 50 100 150 freq [Hz] fase [deg] 3) 0 2 4 6 8 10 12 14 16 18 20 0 0.2 0.4 0.6 0.8 1 modulo [eu] 0 2 4 6 8 10 12 14 16 18 20 -150 -100 -50 0 50 100 150 freq [Hz] fase [deg] 4)                                              692cos 692cos692cos3922cos392sin )cos()(os e 2cos)sin(    t tttt c 0 2 4 6 8 10 12 14 16 18 20 0 0.2 0.4 0.6 0.8 1 modulo [eu] 0 2 4 6 8 10 12 14 16 18 20 -150 -100 -50 0 50 100 150 freq [Hz] fase [deg] 5) 0 2 4 6 8 10 12 14 16 18 20 0 2 4 6 modulo [eu] 0 2 4 6 8 10 12 14 16 18 20 -100 0 100 freq [Hz] fase [deg] 6) 0 2 4 6 8 10 12 14 16 18 20 0 2 4 6 modulo [eu] 0 2 4 6 8 10 12 14 16 18 20 -100 0 100 freq [Hz] fase [deg] 7)   53 262cos553 462cos553 462cos5 5623 4cos55362cos55362cos5 )cos()(os e cos)cos(                                                 ttt ttt c 0 2 4 6 8 10 12 14 16 18 20 0 2 4 6 modulo [eu] 0 2 4 6 8 10 12 14 16 18 20 -100 0 100 freq [Hz] fase [deg] 8) 0 2 4 6 8 10…

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