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06 02 14 testi

Study material for Meccanica dei Solidi, shared by the Studwiz community and reviewed by moderators.

Meccanica dei SolidiSecond midterm

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sez141.001MdS 2013/14 Appello del 11/02/2014 Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.27.03.13 06.02.14 y,Ty My 32 0 θ,Mt z,N Mx mm x,Tx1680-8-16 t=0.6 t=0.6 t=0.4 t=0.6 t=0.6 32 32.6 D E F B A C Calcolo degli sforzi in * con forze baricentriche essendo * il punto B di EB N = 4870 N Ty = 1860 N Mt = 1370 Nmm Mx = 67300 Nmm σa = 500 N/mm 2 E = 200000 N/mm 2 G = 80000 N/mm 2 yG = uo = vo = A = Su * = Cw = Ju = Jv = Jt = σ(N) = σ(Mx) = τ(Mt)d = τ(Tyc) = τ(Tyb)d= τ(Ty)s = τ(Ty)d = σ = τs = τd = σIs = σIIs = σId = σIId = σtresca = σmises = σst.ven = θt = ru = rv = ro = Jp = sez141.002MdS 2013/14 Appello del 11/02/2014 Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.27.03.13 06.02.14 y,Ty My 26 0 θ,Mt z,N Mx mm x,Tx1680-8-16 t=0.6 t=0.6 t=0.4 t=0.6 t=0.6 32 26.6 D E F B A C Calcolo degli sforzi in * con forze baricentriche essendo * il punto B di EB N = 5000 N Ty = 1640 N Mt = 966 Nmm Mx = 57700 Nmm σa = 500 N/mm 2 E = 200000 N/mm 2 G = 80000 N/mm 2 yG = uo = vo = A = Su * = Cw = Ju = Jv = Jt = σ(N) = σ(Mx) = τ(Mt)d = τ(Tyc) = τ(Tyb)d= τ(Ty)s = τ(Ty)d = σ = τs = τd = σIs = σIIs = σId = σIId = σtresca = σmises = σst.ven = θt = ru = rv = ro = Jp = sez141.003MdS 2013/14 Appello del 11/02/2014 Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.27.03.13 06.02.14 y,Ty My 32 0 θ,Mt z,N Mx mm x,Tx1580-8-15 t=0.6 t=0.6 t=0.4 t=0.6 t=0.6 30 32.6 D E F B A C Calcolo degli sforzi in * con forze baricentriche essendo * il punto B di EB N = 5720 N Ty = 1500 N Mt = 1090 Nmm Mx = 82600 Nmm σa = 500 N/mm 2 E = 200000 N/mm 2 G = 80000 N/mm 2 yG = uo = vo = A = Su * = Cw = Ju = Jv = Jt = σ(N) = σ(Mx) = τ(Mt)d = τ(Tyc) = τ(Tyb)d= τ(Ty)s = τ(Ty)d = σ = τs = τd = σIs = σIIs = σId = σIId = σtresca = σmises = σst.ven = θt = ru = rv = ro = Jp =

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