Study material for Meccanica dei Solidi, shared by the Studwiz community and reviewed by moderators.
Study material for Meccanica dei Solidi, shared by the Studwiz community and reviewed by moderators.
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120912ENE.001EQUILIBRIO Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.04.07.12 04.09.12 A B C D E F HGC VGC W HA VD q q EQUAZIONI DI EQUILIBRIO Rotazione globale intorno a E HAb +4VDb = W +2qb 2 Rotazione intorno a B: aste BA BC CD CG 2VDb -HGCb +VGCb = -qb 2 Rotazione intorno a F: aste FB BA BC CD CG HAb +3VDb +2VGCb = qb 2 Traslazione orizzontale: aste CG HGC = qb Matrice di equilibrio HAb V Db H GCb V GCb W qb 2 ϕE 1 4 0 0 1 2 ϕBF 0 2 -1 1 0 -1 ϕFB 1 3 0 2 0 1 = uCG 0 0 1 0 0 1 Soluzione del sistema W qb 2 HAb 1/5 6/5 VDb 1/5 1/5 HGCb 0 1= VGCb -2/5 -2/5 120912ENE.001REAZIONI Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.04.07.12 04.09.12 7/5F F 7/5F 1/2Fb A B 2/5F 1/2Fb 2/5F 1/10Fb B C 2/5F 2/5Fb 2/5F C D 3/5F 2/5F 3/5F 2/5F 3/5Fb E F 4/5F F 3/5Fb 4/5F F Fb F G 4/5F 1/2Fb 4/5F F CG 7√2/5F B F 120912ENE.001DEFORMATA E AZIONI INTERNE Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.04.07.12 04.09.12 1.2 Fb3/EJ A B C D E F G -7/5 -7/5 0 0 2/5 -1 -4/5 -4/5 7√2/5 F 0 -1 2/5 -2/5 3/5 -4/5 0 1 0 F 0 -1/2 -1/2 -1/10 2/5 0 0 3/5 3/5 -1 -1/2 0 0 0 Fb 120912ENE.001PROCEDIMENTO E RISULTATI Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.04.07.12 04.09.12 A = 612. mm 2 Ju = 225968. mm 4 Jv = 40716. mm 4 yg = 32.65 mm N = -2950. N Ty = -2360. N Mx = -1416000. Nmm xm = 12. mm um = -9. mm vm = -32.65 mm σm = N/A-Mv/Ju = -209.4 N/mm 2 xc = 21. mm yc = 9. mm vc = -23.65 mm σc = N/A-Mv/Ju = -153. N/mm 2 τc = 6.361 N/mm 2 σo = √σ 2 +3τ 2 = 153.4 N/mm 2 S * = 3655. mm 3 mm 0 12 18 24 30 42x 0 6 48 54 y 9 σc,τc σm u v 120912ENE.002EQUILIBRIO Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.04.07.12 04.09.12 A B C D E F HGC VGC W HA VD q q EQUAZIONI DI EQUILIBRIO Rotazione globale intorno a E HAb +4VDb = W +2qb 2 Rotazione intorno…
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