1692799655 Exam June 2022 solutions

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Activity Immediate Predecessor Duration (Weeks) Duration Reduction (Crashing) Total Crashing Cost (€) A - 3 1 28 000€ B - 6 3 6 000€ C A 4 2 42 000€ D A 3 2 40 000€ E D 4 3 75 000€ F D 2 1 11 000€ G E,F 2 1 32 000€ H B,C,G 2 - - Exercise 1 The following project is assigned. Identify the critical path. Consider the possibility to crash the activities as shown in the following table. Identify the optimal solution according to a crashing programme. A penalty of 30 000€ for each week of delay is applied in case the project is not concluded before week 8. At the end of each step of the crashing algorithm write which is the margin gained and the critical path/s. 3 74 C 8 125 0 66 B 6 126 3 63 D 3 60 6 104 E 6 100 6 82 F 8 102 The critical path is A-D-E-G-H. The project duration is 14 weeks. Solution 0 33 A 0 30 10 122 G 10 120 12 142 H 12 140 Exercise 1 The following project is assigned. Identify the critical path. Consider the possibility to crash the activities as shown in the following table. Identify the optimal solution according to a crashing programme. A penalty of 30 000€ for each week of delay is applied in case the project is not concluded before week 8. At the end of each step of the crashing algorithm write which is the margin gained and the critical path/s. Activity Immediate Predecessor Duration (Weeks) Duration Reduction (Crashing) Total Crashing Cost (€) Unitary Crashing Cost A - 3 1 28 000€ 28 000€ B - 6 3 6 000€ 2 000€ C A 4 2 42 000€ 21 000€ D A 3 2 40 000€ 20 000€ E D 4 3 75 000€ 25 000€ F D 2 1 11 000€ 11 000€ G E,F 2 1 32 000€ 32 000€ H B,C,G 2 - - Crash D, as it is the most convenient activity. Indeed, A is less convenient, E is not economically convenient, as crashing it by 3 weeks would produce a project duration reduction of only two weeks (and…