Study material for Meccanica dei Solidi, shared by the Studwiz community and reviewed by moderators.
Study material for Meccanica dei Solidi, shared by the Studwiz community and reviewed by moderators.
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MdS.001Prova in itinere 2 - lunedì 23/1/12 Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.23.12.11 18.01.12 y,Ty My 85 75 20 0 θ,Mt z,N Mx mm x,Tx501510-10-15-50 80 100 85 BA C D E F GH I J K L Calcolo degli sforzi in * con forze baricentriche N = 51400 N Ty = 170000 N Mx = 877000 Nmm σa = 50 N/mm 2 E = 200000 N/mm 2 G = 80000 N/mm 2 yG = 28.31 mm A = 3400 mm 2 Su * = 8129 mm 3 Ju = 2223609 mm 4 Jv = 1725834 mm 4 σ(N) = 15.12 N/mm 2 σ(Mx)= 20.39 N/mm 2 τ(Ty) = 20.72 N/mm 2 σ = 35.5 N/mm 2 τ = 20.72 N/mm 2 σI = 45.03 N/mm 2 σII = -9.529 N/mm 2 σtresca= 54.56 N/mm 2 σmises= 50.48 N/mm 2 σst.ven= 47.42 N/mm 2 ru = 25.57 mm rv = 22.53 mm ro = 34.08 mm u v 28.31 MdS.002Prova in itinere 2 - lunedì 23/1/12 Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.23.12.11 18.01.12 y,Ty My 83 75 20 0 θ,Mt z,N Mx mm x,Tx501510-10-15-50 79 100 83 BA C D E F GH I J K L Calcolo degli sforzi in * con forze baricentriche N = 55500 N Ty = 161000 N Mx = 892000 Nmm σa = 50 N/mm 2 E = 200000 N/mm 2 G = 80000 N/mm 2 yG = 27.31 mm A = 3340 mm 2 Su * = 6443 mm 3 Ju = 2034155 mm 4 Jv = 1721334 mm 4 σ(N) = 16.62 N/mm 2 σ(Mx)= 22.67 N/mm 2 τ(Ty) = 17 N/mm 2 σ = 39.28 N/mm 2 τ = 17 N/mm 2 σI = 45.62 N/mm 2 σII = -6.334 N/mm 2 σtresca= 51.95 N/mm 2 σmises= 49.09 N/mm 2 σst.ven= 47.2 N/mm 2 ru = 24.68 mm rv = 22.7 mm ro = 33.53 mm u v 27.31 MdS.003Prova in itinere 2 - lunedì 23/1/12 Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.23.12.11 18.01.12 y,Ty My 85 73 20 0 θ,Mt z,N Mx mm x,Tx501510-10-15-50 79 100 85 BA C D E F GH I J K L Calcolo degli sforzi in * con forze baricentriche N = 46500 N Ty = 133000 N Mx = 1120000 Nmm σa = 50 N/mm 2 E = 200000 N/mm 2 G = 80000 N/mm 2 yG = 28.58 mm A = 3420 mm 2 Su * = 9616 mm 3 Ju = 2265125 mm 4 Jv = 1729000 mm 4 σ(N) = 13.6 N/mm 2…
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