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ExamSecond midtermExam paper only

18 01 12 Testi

Study material for Meccanica dei Solidi, shared by the Studwiz community and reviewed by moderators.

Meccanica dei SolidiSecond midterm

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MdS.001Prova in itinere 2 - lunedì 23/1/12 Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.23.12.11 18.01.12 y,Ty My 85 75 20 0 θ,Mt z,N Mx mm x,Tx501510-10-15-50 80 100 85 BA C D E F GH I J K L Calcolo degli sforzi in * con forze baricentriche N = 51400 N Ty = 170000 N Mx = 877000 Nmm σa = 50 N/mm 2 E = 200000 N/mm 2 G = 80000 N/mm 2 yG = A = Su * = Ju = Jv = σ(N) = σ(Mx)= τ(Ty) = σ = τ = σI = σII = σtresca= σmises= σst.ven= ru = rv = ro = MdS.002Prova in itinere 2 - lunedì 23/1/12 Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.23.12.11 18.01.12 y,Ty My 83 75 20 0 θ,Mt z,N Mx mm x,Tx501510-10-15-50 79 100 83 BA C D E F GH I J K L Calcolo degli sforzi in * con forze baricentriche N = 55500 N Ty = 161000 N Mx = 892000 Nmm σa = 50 N/mm 2 E = 200000 N/mm 2 G = 80000 N/mm 2 yG = A = Su * = Ju = Jv = σ(N) = σ(Mx)= τ(Ty) = σ = τ = σI = σII = σtresca= σmises= σst.ven= ru = rv = ro = MdS.003Prova in itinere 2 - lunedì 23/1/12 Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.23.12.11 18.01.12 y,Ty My 85 73 20 0 θ,Mt z,N Mx mm x,Tx501510-10-15-50 79 100 85 BA C D E F GH I J K L Calcolo degli sforzi in * con forze baricentriche N = 46500 N Ty = 133000 N Mx = 1120000 Nmm σa = 50 N/mm 2 E = 200000 N/mm 2 G = 80000 N/mm 2 yG = A = Su * = Ju = Jv = σ(N) = σ(Mx)= τ(Ty) = σ = τ = σI = σII = σtresca= σmises= σst.ven= ru = rv = ro =

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