Document information
- University
- Politecnico di Milano
- Degree programme
- Energy Engineering
- Subject
- Meccanica dei Solidi
- Academic year
- 2012-2013
- Classification
- Exam · Full exam
- Content
- Solution only
- Original format
- Text
- Searchable text
Study material for Meccanica dei Solidi, shared by the Studwiz community and reviewed by moderators.
Study material for Meccanica dei Solidi, shared by the Studwiz community and reviewed by moderators.
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A1.001REAZIONI Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.27.03.13 13.06.13 2F F 2F F 2Fb A B 2F F 2Fb 2F 2F 1/2Fb B C 3/2F 2F 1/2Fb 3/2F 2F 3/2Fb C D 3/2F 2F 3/2Fb 3/2F 2F 3Fb D E 2F 2Fb 2F 2Fb E F 2F 2Fb 2F FG 1/2F 1/2F C H 1/2F Fb 1/2F Fb H E A1.001AZIONI INTERNE Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.27.03.13 13.06.13 -1 -2 -2 -3/2 22 0 0 0 1/2 F 2 -1 -2 -2 -3/2 0 2 -1/2 1/2 0 F 0 22 1/2 1/2 -3/2 -3/2 -3-2 -2 -2 0 0 0 1 1 Fb A1.001RISULTATI NUMERICI Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.27.03.13 13.06.13 A = 540. mm 2 Ju = 154030. mm 4 Jv = 37908. mm 4 yg = 36.6 mm N = 1000. N Ty = -750. N Mx = -885000. Nmm xm = 18. mm um = -3. mm vm = -36.6 mm σm = N/A-Mv/Ju = -208.4 N/mm 2 xc = 21. mm yc = 15. mm vc = -21.6 mm σc = N/A-Mv/Ju = -122.3 N/mm 2 τc = 2.125 N/mm 2 σo = √σ 2 +3τ 2 = 122.3 N/mm 2 S * = 2619. mm 3 mm 0 18 24 42x 0 48 54 y 15 σc,τc σm u v A1.001 @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.27.03.13 13.06.13 A1.002REAZIONI Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.27.03.13 13.06.13 2F F 2F F 2Fb A B 2F F 2Fb 2F 2F 1/2Fb B C 3/2F F 1/2Fb 3/2F F 1/2Fb C D 3/2F F 1/2Fb 3/2F F 2Fb D E 2F 2Fb 2F 2Fb E F 2F 2Fb 2F FG 1/2F F 1/2F F C H 1/2F F Fb 1/2F F H E A1.002AZIONI INTERNE Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.27.03.13 13.06.13 -1 -2 -2 -3/2 12 0 1 1 1/2 F 2 -1 -2 -1 -3/2 0 2 -1/2 1/2 -1 F 0 22 1/2 1/2 -1/2 -1/2 -2-2 -2 -2 0 0 0 1 0 Fb A1.002RISULTATI NUMERICI Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.27.03.13 13.06.13 A = 756. mm 2 Ju = 165564. mm 4 Jv = 74844. mm 4 yg = 39. mm Ty = 1440. N Mx = -921600. Nmm xm = 18. mm um = -3. mm vm = -39. mm σm = -Mv/Ju = -217.1 N/mm 2 xc = 21. mm yc = 16. mm vc = -23. mm σc = -Mv/Ju = -128. N/mm 2 τc =…
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