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Study material for Meccanica dei Solidi, shared by the Studwiz community and reviewed by moderators.

Meccanica dei SolidiFull exam

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A1.001REAZIONI Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.23.12.11 31.01.12 2F 11Fb 2F 9Fb A B 4F 4F 4F 4F 4Fb B C 4F 4F 4Fb 4F C D 4F4F 4Fb DE 4F 8Fb 4F 8Fb E F 6F 4F 10Fb 6F 4F 6Fb BG 6F 4F 6Fb 4F G H 4F 4F 4Fb H E A1.001AZIONI INTERNE Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.23.12.11 31.01.12 0 4 4 4 0 -4 6 -4 -4 0 F -2 -4 4 0 4 0 -4 -6 0 4 F 11 9 0 -4 -4 0 0 4 8 8 10 6 6 0 0 4 Fb A1.001RISULTATI NUMERICI Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.23.12.11 31.01.12 A = 612. mm 2 Ju = 225968. mm 4 Jv = 40716. mm 4 yg = 32.65 mm N = 1800. N Ty = -1200. N Mx = 1410000. Nmm xm = 12. mm um = -9. mm vm = -32.65 mm σm = N/A-Mv/Ju = 206.7 N/mm 2 xc = 21. mm yc = 8. mm vc = -24.65 mm σc = N/A-Mv/Ju = 156.7 N/mm 2 τc = 3.106 N/mm 2 σo = √σ 2 +3τ 2 = 156.8 N/mm 2 S * = 3510. mm 3 mm 0 12 18 24 30 42x 0 6 48 54 y 8 σc,τc σm u v A1.001 @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.23.12.11 31.01.12 A1.002REAZIONI Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.23.12.11 31.01.12 2F 7Fb 2F 5Fb A B 4F 4F 4F 4F 4Fb B C 4F 4F 4Fb 4F C D 4F4F 4Fb DE 4F 4Fb 4F 4Fb E F 6F 4F 6Fb 6F 4F 2Fb BG 6F 4F 2Fb 4F 4Fb G H 4F 4Fb 4F H E A1.002AZIONI INTERNE Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.23.12.11 31.01.12 0 4 4 4 0 -4 6 -4 -4 0 F -2 -4 4 0 4 0 -4 -6 0 4 F 7 5 0 -4 -4 0 0 4 4 4 6 2 2 -4 -4 0 Fb A1.002RISULTATI NUMERICI Nome: @ Adolfo Zavelani Rossi, Politecnico di Milano, vers.23.12.11 31.01.12 A = 828. mm 2 Ju = 250978. mm 4 Jv = 77652. mm 4 yg = 35.87 mm N = 2940. N Ty = -1960. N Mx = 1499400. Nmm xm = 12. mm um = -9. mm vm = -35.87 mm σm = N/A-Mv/Ju = 217.8 N/mm 2 xc = 21. mm yc = 10. mm vc = -25.87 mm σc = N/A-Mv/Ju = 158.1 N/mm 2 τc = 5.491 N/mm 2 σo = √σ 2 +3τ 2 = 158.4 N/mm 2 S * = 4219. mm 3 mm 0…

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