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- Politecnico di Milano
- Degree programme
- Biomedical Engineering
- Subject
- Bioengineering of Physiological Control Systems
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- Notes · Complete set
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Theory Bioengineering of Physiological Control Systems
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HP1:increaseunbloodvolumeorcardiacoutput. wetalkaboutaversatilesystem(60beats/nu ·asthecoisnotastraightD intime(s)Aresowetalkaboutangvalve HPC:RC=LCOnotapathologicalcase nobloodlostinthesulmonarysystemIdisturbance ↑· Tu t-BACK IPLANT:HEART(bloodvolume) offerent STRETCH I y:volume/pressureinnightatrum gebresx:increaseinvenousreturn -chreceptorssensor:volumereceptors,atrulstrel CC:cardiaccontractulityEFFECT.moseaseintheneuraledischangeoftheafferentfibres V. V=venousreturn TPR=totalperipheralresistance SBP= systolicbloodpressureDBP=diastolicbloodpressureABP=anterialbloodpressure :Vasodulators MAP=CO+TPR perI MAP=SBP+1 DBP y(t)= yz=(t)+yzs(t) ZeroInput0. 251. 25+yz=0 2)yz(t)- 0. 255212(s)- 0.255- 0. 25+1.25s4z(s)- 1. 23+yz(s)=0 Yzi(s)= 0.255+1.5= 0.255+1. 255+1 = HEAVYSIDEDECOMPOSITI Pr=s=-1-> Yz(s)= -- yz(t)= 2- 1(Yz(s))= (et+2 - 4)u(t)P= s=- 4=- 33 Zero-statep. 25 1. 25+yzs=0. 25 x+1 2(yzs(t))0.2552yzs(s)+1.25s4zs(s)+Yzs(s)=0.25sX(s)+2.25x(s)= (0. 5+1. 25)7 ofx(t)=u(t)= (22(u(t))= E=X(s) Yzs(s)= 0.55+1. 25 25+3=5(0.255+1. 255+1)= s(s+1)(s+4) Pe=4)= = =- 1, P== = -Yzs(s)= S--- yzs(t)= 2+ (zs(s))= (7- e -T- 1(u(t) y(t)= yz(t)+yzz(t)= (+et- 1H)u(t) *OUIJTDBTFJIBWFUIFTJHOBMT OPUUIF0%&T8FNFBTVSFUIFPVUQVU 2(u(t))= E Polesrepresentdelays: 2 (eu(t))=ZERO. STATE Laplacetransform: 5Yzs(s)+45Yzs(s)+3Yzs(s)=2X(s) ITRANSFERFUNCTION: H(S)=*32+15+3= (s+29(s+3)= 2+ 3 Pr= stsls=-1= H(s)=- h(t)=2(H(s))= (e+- Ge - 3)u(t)fotoPr= stels=-3 - OUTPUT: V(t)=x0(1- e-St)u(t) t -x(t)=xu(t)- D H(s)=)soIneedthelaplacetransform -X(s)= 2(x(t))=-y(s)= 2(V(t))=2(xou(t)- e- Su(t))= =- x)= 20 45)IH(s)= +3)= h(t)=2"(H(s))= 5 -u(t)IMPULSERESPONSE STEPRESPONSEg(t)= (2(2)dz= 1 ge-32dz=- 2- 3t)= (1- e- St)u(t)fortzo
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