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03 Autovalori 2

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Analisi Matematica 2By topic

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false:a)Antarsonomatricisimilie)Antarhannoseistai autovaloi1) A,Awhannolostenodeterminante a)Antshannolostenopdinomiocatteristico. a)AneAzsonosimiliOkpeschesipuòadgeriscamicdabasedaBarreviceversar b)Eca:teorencediBinet(farelosvaltaprossimal e)Vera a)Vera 3104/2023 "firstaue'104/2022 1)6= (i,es,edefinitainRPdatatodiprodotoscalare standardsiaF:RY->R3elunicoapplicazioneamoretale che(CT)= e-e+IesFle)= ai+e-2es#(15)=(1- a)e- 22+ 4es b)perqualevalorediatRilvettoree-+2èunautoretto ⊥ediI?Pertalevalore,epariete,determinarieunabass- artonormaledeR3formatadaautorettorede'F e)Pestoa= 2Sverificarecheloscalare3èunautovaloredi Festabilire,aest,unabandiRSformatada autoree I=-2]e)A= eerasF(E)=xXER Ao*No 1- a+ 2(1- a) 1- a+2- 2a= 6 - 3a=3 - 1- 1- 4 - 6= - xx= 6 [2+2+ 8(E)E12=2X- x= 6 pera=-1eunautovettorediFcorrispondenteall'autovalo- xx=6 A1= 1- 12.esisteunorbaudiREartonormale IformatadorautovettandiF-21 - e]2- 24 perx= 6hosautorettore=[1]tr(A1)= 6= x1+ x2+ Xy 12+ y= 0 = 3,50(0)=2= 5πs,:An=0A = 1 M(A-1)=1 Ru()= 2([5];[4]) *= j)ai= (B,532] = [8]B+ [8]aer B= ([];t];[5]}-I,ts=0 Ok- - - Lbs,83=0 Ok - brTrbg <V2,)= 0 NO procedimento(algoritmodiGramSchindt f= b= [4]f= 6- 81= 787-0= [8] fz= bg- --ab= (3)= T8]= E(b,fi)=- 2+2=0 Il= 1+4=5 (b,,fz)= - 2 Ile S 1111=55 elir)entreistitBx= {[8]:][7 D=P-A1 Peatogonale (PKeJIptp-1 IP= - Y)- 8- )+ Y/48+4rs)= +=1 interoeroeeIdet(PA_,P)= 1".(11)= det(D-1)= 0=0=> IP1=IPTexende

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