Document information
- University
- Politecnico di Milano
- Degree programme
- Energy Engineering
- Subject
- Statistica per L'ingegneria
- Academic year
- 2014-2015
- Classification
- Exam · First midterm
- Content
- Exam paper only
- Original format
- Text
- Searchable text
Study material for Statistica per L'ingegneria, shared by the Studwiz community and reviewed by moderators.
Study material for Statistica per L'ingegneria, shared by the Studwiz community and reviewed by moderators.
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d v v=h·d h h km/sM p c h [0 10) [10 20) [20 30) [30 40) [40 50) [50 60) [60 70) [70 80) [80 90) [90 100) [100 110) [0,10) [10 20) [20,30) [30,40) [40,50) [50 60) [60 70) [70 80) [80 90) [90 100) [100 110) Istogramma di H − 11 classi H [km/s * Mpc] Density 020406080100120 0.0000.0050.0100.0150.020 n= 36 pn 1 + log2n [0,20) [20 40) [40,60) [60,80) [80,10) [100 120) Istogramma di H − 6 classi H [km/s * Mpc] Density 020406080100120 0.0000.0050.0100.015 h36'(2·5+0·15 + 2·25 + 2·35 + 6·45 + 7·55 + 5·65 + 6·75 + 3·85 + 2·95 + 1·105)/36 = 58.61 Q32[70 80) 0.75'0.6667 + (Q3 70)·0,0167 =)Q3'75. X fX(x)= ( ↵(x+ 1)3, 1x1, 0, . ↵ fX FX X X X 8 >< >: ↵ 0, 1= Z1 1 ↵(x+ 1)3dx=↵(x+ 1)4 4 1 1 =)↵=1/4. 1x1 FX(x)= Zx 1 1 4(t+ 1)3dt=(x+ 1)4 16 FX(x)= 8 >< >: 0,x < 1, 1 16(x+ 1)4, 1x1, 1,x > 1. −2−1012 0 2 4 6 8 Densità x f(x) mediamediana −2−1012 0.00.20.40.60.81.0 Ripartizione x F(x) mediamediana P(X>0) = 1 P(X0) = 1 FX(0) = 1 1 16=0.9375 m>0 P(X0)<0.5 m<E[X] fX FX(m)=0.5=)1 16(m+ 1)4=1 2=)m+1=4p 8=)m=0.6817. E[X]= Z1 1 x·1 4(x+1)3dx= 1 4 x5 5+3 4 x4 4+3 4 x3 3+1 4 x2 2 1 1 =1 4 1 5+1 5 +1 4[1 + 1] =6 10=0.6. n X X⇠B(363,0.92) 363·0.08 = 29.04>5 363·0.92 = 333.96>5 X⇠B(363,0.92)'N(333.96,26.7168). P(X= 363) = 0.92363=7.2·10 14 P(X325) =P(X325.5)' ⇣325.5 333.96p 26.7168 ⌘ = ( 1.64) = 1 (1.64) = 0.0508 = 5.08% P(X325) = 0.0550 = 5.5% Y n Y⇠B(n,0.92) n P(Y325)<0.025 n>363 Y⇠B(n,0.92)'N(0.92n,0.0736n). 0.025>P(Y325) = ✓325.5 0.92np 0.0736n ◆ 325.5 0.92np 0.0736n< z0.025= 1.96 n>364.84 n= 365 P(Y>330)'1 ⇣330.5 365·0.92p 365·0.92·0.08 ⌘ =0.8467 = 84.67%. P(Y>330) = 0.8467 = 84.67%.
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