Document information
- University
- Politecnico di Milano
- Degree programme
- Energy Engineering
- Subject
- Statistica per L'ingegneria
- Academic year
- 2013-2014
- Classification
- Exam · Second midterm
- Content
- Exam paper only
- Original format
- Text
- Searchable text
Study material for Statistica per L'ingegneria, shared by the Studwiz community and reviewed by moderators.
Study material for Statistica per L'ingegneria, shared by the Studwiz community and reviewed by moderators.
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X X λ n X1,...,X n λ = E[X] ˆλ = Xn. ˆλ σ = √ Var(X) ˆσ = √ ˆλ = √ Xn. ˆσ λ ˆλ n ˆλ − λ√ bλ n ≃ N (0, 1). γ λ X 23, 18, 20, 26, 20, 23, 12, 20, 16, 35. λ σ λ γ =0 .95 E[ˆλ] − λ =0 MSE(ˆλ)=V a r (ˆλ)= λ/n se(ˆλ)= √ Var(ˆλ)= √ λ/n ˆλ ≃ N ( λ, λ n ) E[ˆσ] − σ = E [√ ˆλ ] − λ ≃ √ E[ˆλ] − λ =0 MSE(ˆσ) ≃ Var(ˆσ) ≃ λ n ( 1 2 √ λ )2 = 1 4n se(ˆσ)= √ Var(ˆσ) ≃ √ 1 4n ˆλ ± √ ˆλ n z 1−γ 2 ˆλ =2 1.3 ˆσ =4 .6 se(ˆλ)=1 .5 se(ˆσ)=0 .2 21.3 ± 2.9 (18.4 , 24.2) p 120 120 α 120 78 120 102 p X2010 = = { 1, 0, ∼ B(p2010) X2014 = = { 1, 0, ∼ B(p2014) pk = k H0 : p2010 ≥ p2014 H1 : p2010 <p 2014 X2010,1,...,X 2010,120 B(p2010) X2014,1,...,X 2014,120 B(p2014) Rα : Z0 = ˆp2010 − ˆp2014√ ˆp ∗(1 − ˆp) ∗( 1 120 + 1 120 ) < −zα ˆpk = ∑120 j=1 Xk,j 120 , ˆp = ∑120 j=1 X2010,j + ∑120 j=1 X2014,j 240 . ˆp2010 =0 .65 ˆp2014 =0 .85 ˆp =0 .75 Z0 = −3.577708764 < −zα = −1.645, 0.05 p α Z0 = −3.577708764 = −zα zα =3 .577708764 1 − α = Φ(zα ) = Φ(3 .577708764) = 0 .9998266903 α =0 .0001733097 = 1 .7 · 10− 4 Y = y =2 1 3.6735 s2 y =1 1 5.6454. Y Y Y x Y = β0 + β1X + ϵ, ϵ ∼ N (0,σ 2). Y x 22◦ Y
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